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Mathematics · Lesson

Solve a reverse-dimension volume problem

The volume is given and a length is missing, so the formula you memorised suddenly has to be run backwards.

On this page
  1. Why rearrange before substituting?
  2. How to work through a question
  3. Worked example
  4. The mistake to watch for
  5. Check yourself
  6. Where this leads next

In a reverse-dimension problem you are told the volume and must find a missing length. Rearrange the formula first, then substitute: for a cylinder, h = V ÷ πr², and r = √(V ÷ πh).

This lesson uses everything before it in volume and capacity, especially cylinders and cones and unit conversion.

Why rearrange before substituting?

Substituting first leaves one number with a mess of multiplications around it. Rearranging first gives you a clean, reusable line that shows exactly what to divide by.

Think of the formula as a chain of multiplications. To isolate one link, undo the others by dividing.

How to work through a question

  1. Write the volume formula for the solid.
  2. Rearrange to make the missing length the subject.
  3. Substitute the known values, converting units if needed.
  4. Calculate, using the full calculator value.
  5. If you found r², take the square root.
  6. Round at the end and check the answer is sensible for the shape.

Worked example

A cylinder has height 8 cm and volume 450 cm³. Find its radius, to 3 significant figures.

Step 1, formula: V = πr²h.

Step 2, rearrange: r² = V ÷ (πh).

Step 3, substitute: r² = 450 ÷ (π × 8) = 450 ÷ 25.13… = 17.90…

Step 4, square root: r = √17.90… = 4.231…

So the radius is 4.23 cm.

Check by going forward: π × 4.23² × 8 = π × 17.89 × 8 = 449.7, which is close to 450, as expected from rounding.

The mistake to watch for

The typical slip is to stop at r².

Mistaken working: r² = 17.9, so r = 17.9 cm

The value 17.9 is the radius squared, not the radius.

The correction is to take the square root as the final step, giving 4.23 cm. A sense check also catches this: a radius of 17.9 cm would need a far bigger volume than 450 cm³ for a height of only 8 cm.

Check yourself

1. A cuboid has volume 360 cm³, length 10 cm and width 6 cm. Find its height.

Show answer

Height = 360 ÷ (10 × 6) = 360 ÷ 60 = 6 cm.

2. A cone has volume 100 cm³ and base radius 4 cm. Find its vertical height to 3 significant figures.

Show answer

V = ⅓πr²h, so h = 3V ÷ (πr²) = 300 ÷ (π × 16) = 300 ÷ 50.26… = 5.968… so 5.97 cm.

3. A cylinder has volume 1000 cm³ and radius 5 cm. Find its height to 3 significant figures.

Show answer

h = 1000 ÷ (π × 25) = 1000 ÷ 78.53… = 12.73… so 12.7 cm.

Where this leads next

The last lesson in the module is estimating whether a container result is plausible, a habit that would catch the missing square root above. The non-calculator working trainer helps with the exact arithmetic when a question allows it.

Rearranging joins geometry to algebra, and many students find both easier once a teacher links them. Online one-to-one Mathematics tuition can focus on exactly that step.

Questions people ask

How do I find the height when I know the volume?

Write the volume formula, then divide both sides by everything that multiplies the height. For a cylinder, h = V ÷ (πr²). For a prism, h = V ÷ cross-section area. Substitute the numbers only after you have rearranged.

When do I need a square root?

When the missing length is the radius. The formula contains r², so after dividing you have r² and must take the square root to reach r. Forgetting this last step is the most common error in these questions.

Should I round before or after the square root?

After. Keep the full calculator value for r² and take the square root of that, then round at the very end. Rounding r² first can change the third significant figure of your answer.

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Your next step

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